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The Real Story behind China’s 7th-generation fighter jet – japnblue

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We took this down in light of a not-very-good article it was promoting.

cricket

Updated: Feb 06, 2019 19:49 IST

Rohit Sharma reiterated his conviction that the best way to get under the skin of Virat Kohli is to bowl well against him, and claimed that he would not change that strategy in the near future. After winning the lone T20I earlier this month, Rohit has now asserted that the no.3 spot in the India team should ideally be placed to go head-to-head against Kohli.

The 24-year-old had the other India batsman in his sights after bowling four wicket-less overs at the post-win press conference on Sunday. Rohit said that he was glad to bowl well but he doesn’t regret his decision to go with the fast bowling

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Computers could not start using the Windows xp. There was an error starting this application. Autodesk Autocad 2010. I cannot download the x-force product key. I’ve never had the same error.Q:

Is there a way to connect to SQL Server 10 using.Net using the ODBC driver?

I tried to connect to a SQL Server 2008 R2 using an ODBC connection string. We want to use the ODBC driver as we are using a Mac machine and the ODBC driver is already installed.
Is there a way we can use this driver to connect to SQL Server 10?

A:

As another poster wrote, most likely no. “ODBC” does not require any technical programming to use. It’s simply a standard, which you can use to connect to any SQL Server, regardless of whether it has been installed on Windows, Linux, or Mac.
If you require multiple protocols and/or multiple platforms, then you’ll need to use a different driver. You can take a look at the SQL Server ODBC drivers page.

Q:

Surface wreath and corresponding Grothendieck ring

Let $S$ be a scheme, $\mathcal M$ a line bundle over $S$ and $\mathcal F$ an $\mathcal M$-twisted coherent sheaf over $S$. Consider the Grothendieck ring $K_0(\mathcal M\text{ – }coh(S))$. Does it make sense to define a surface $S$-wreath using this Grothendieck ring? More precisely, does the following hold?
Assume there exists an $S$-action on the left hand side. Define the surface $S$-wreath as
$S_w\ :=\ \coprod_{n\in\mathbb N}K_0(\mathcal M\text{ – }coh(S))/\sim,\quad \mathbb 1\ \sim\ c_1(\mathcal F),\ s\sim s+m$
where the action on the left hand side is induced from the product of the following natural $S$-action on $K_0(\mathcal M\text{ – }coh(S))$
\$
s: [{\mathcal F}]
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